Question

3. The base and altitude of a triangular garden is 100m and 25m respectively. Find the cost of landscaping the garden at the rate of $ 10 per m ² *

Answer 1

Given

The base and altitude of a triangular garden is 100m and 25m respectively.

To find

Find the cost of landscaping the garden at the rate of $ 10 per m ²

Solution

• Base of triangular garden = 100m
• Altitude of triangular garden = 25m
• Area of triangular garden = ?

As we know that

Area of triangle

→ ½ × base × height

→ ½ × 100 × 25

→ 50 × 25

→ 1250m²

The cost of landscaping the garden for 1m² = $10

Cost of landscaping the garden for 1250m²

→ 1250*10

→ $12500

Hence, the cost of landscaping the garden is $12500

Answer 2

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The base and altitude of a triangular garden is 100m and 25m respectively. Find the cost of landscaping the garden at the rate of $ 10 per m².

$\bf  {\underline {\underline{✤ ƛƝƧƜЄƦ}}}$

➡Cost of landscaping the garden is $12500

$\bf  {\underline {\underline{✤ ƓƖƔЄƝ}}}$

• Base of triangular garden = 100m
• Altitude of triangular garden = 25m

$\bf  {\underline {\underline{✤ ƬƠ \: \: ƇƛLƇƲLƛƬЄ}}}$

• Cost of landscaping the garden at the rate of $ 10 per m²

$\bf  {\underline {\underline{✤ ƑƠƦMƲLƛ \: \: ƬƠ \: ƁЄ \: \: ƲƧЄƊ}}}$

Area of Triangle

$\bf \implies \blue{ \frac{1}{2} \times base \times height}$

$\bf  {\underline {\underline{✤ SƠLƲƬƖƠƝ}}}$

Base of triangular garden = 100m

Altitude of triangular garden = 25m

$\bf Area \: of △ = \frac{1}{2} \times base \times height$

$\bf\implies \frac{1}{2} \times 100 \times 25$

$\bf\implies 1 \times 50 \times 25$

$\bf\implies 1250 {m}^{2}$

Total Cost of landscaping the garden at the rate of $ 10 per m² is :-

$\bf \implies area \: of \: garden \times rate \: of \: landscaping$

$\bf \implies 1250 \times 10$

$\bf \implies 12500$

Therefore, Total Cost of landscaping the garden at the rate of $ 10\: per\: m²\: is $12500.