Question

3. The base of a parallelogram is twice its altitude. If the area of parallelogram is 392 m², find the base and altitude​

Answer 1

Answer:

Let the base(b) be 'x'

Given altitude is twice the base

It means,altitude(h) = 2x

Area of a parallelogram = bh

Given area of the parallelogram = 392 m²

⇒(bh)=392m²

⇒(x)(2x)=392m²

⇒2x²=392m²

⇒x²=392m²/2

⇒x²=196m²

⇒x=√196m²

⇒x=14m.

Therefore,the base of the parallelogram(x)=14m and

                the altitude of the parallelogram(2x)=2(14)=28m

Answer 2

Step-by-step explanation:

let the altitude be =x

base =2x

area of parallelogram =altitude X base

392 = x×2x

392 =2xsquare

x square=392÷2=196

x=14

altitude =14m

base =2×14=28m