3. The brakes applied to a car produce an acceleration of 12m/s in the opposite directions of motion. If the car takes 4s to stop after the application of brakes, calculate the distance travelled during the time.
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Answer:
the distance traveled this time is 13 km
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v = u + at
0 = u + (-12)(4)
0 = u - 48
u = 48
s = ut + 1/2 at^2
s = 48(4) + 1/2 (-12)(4)^2
s = 192 + 1/2 (-12)(16)
s = 192 + 1/2 (-192)
s = 192 - 96
s = 96
Therefore the distance travelled is 96m.
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