Question

3. The distance between Akola and Bhusawal is
168 km. An express train takes 1 hour less
than a passenger train to cover that distance.
Find the average speed of each train, if the
average speed of the express train is more by
14 km/h than that of the passenger train​

Answer 1

Answer:

Step-by-step explanation

Given:

distance = 168 km

let time taken by  express train = x

then ,

the time taken by passenger train = x + 1

so,  168/ x - 14 = 168/x+1

by l.c.m

(168- 14 x )/x = 168/x + 1

168 - 14 x = 168x / x+ 1

168x - 14x * x + 168 - 14x = 168

(168 - 14 )(x + 1 ) = 168

154 ( x + 1 ) = 168

x + 1 = 168/ 154

x = 84 / 77 - 1

by lcm

x = 1 / 11

speed of express train = 168 * 11

speed of passenger train = 168 /  1/11 - 1

= 16 . 8 * 11