Question

3) The distance between the points P(2, -3) and Q(10, y ) is 10 units.
Complete the following activity -10 find the value of y.
PQ' = ...... + [....... (by distance formula)
10² = (...)+(..)
y² + ( ............) y- (... ..) = 0
(y + ...) (y- . ..) = 0
y = ................ or.........

value of y is - 9 or 3.​

Answer 1

Answer:

3

Step-by-step explanation:

PQ = √(10-2)² + (y+3)²

10 = √64+( y+3)²

100-64 = (y+3)²

√36 = y+3

6-3 = y

y = 3..