3. The Edges of a Triangular Board are Given as 6cm, 8cm, and 10 cm.
What will be the Cost of Painting it at the Rate of 9 Paisa/ cm² is
Answers
Answer:
the edges of a trianglular board are a = 6 cm, b=8 cm and c=10 cm. Now, semi-perimeter of a triangular board. Hence, the cost of triangular board is rupee 2.16.
Step-by-step explanation:
mark as brainliast
Step-by-step explanation:
Given :-
The Edges of a Triangular Board are 6cm, 8cm, and 10 cm.
To find :-
What will be the Cost of Painting it at the Rate of 9 Paisa/ cm² ?
Solution :-
Method-1:-
Given that
The Edges of a Triangular Board are 6cm, 8cm, and 10 cm.
Let a = 6 cm , b = 8 cm and c = 10 cm
We know that
Area of a triangle whose sides are a , b and c units by Heron's formula
√[S(S-a)(S-b)(S-c)] sq.units
Where, S = (a+b+c)/2 units
Now,
S = (6+8+10)/2 cm
=> S = 24/2 cm
=> S = 12 cm
Now,
Area of the given triangular board
=>√[12(12-6)(12-8)(12-10)] cm²
=> √(12×6×4×2) cm²
=> √576 cm²
=> 24 cm²
Area of the triangular board = 24 cm²
Given that
The cost of painting it per 1 cm² = 9 paisa
The total cost of painting the total board of 24 cm²
=> 24×9 paisa
=> 216 paisa
Or
=> 216/100 Rupees
=> Rs. 2.16
Method-2:-
The Edges of a Triangular Board are 6cm, 8cm, and 10 cm.
Let a = 6 cm , b = 8 cm and c = 10 cm
It is clear that
They are the sides of the right angled triangle.
So,
Area of the triangle = (1/2)ab sq.units
=> (1/2)×6×8
=> 48/2 cm²
=> 24 cm²
Area of the triangular board = 24 cm²
Given that
The cost of painting it per 1 cm² = 9 paisa
The total cost of painting the total board of 24 cm²
=> 24×9 paisa
=> 216 paisa
Or
=> 216/100 Rupees
Since , 1 rupee = 100 paisa
=> Rs. 2.16
Therefore, The total cost = Rs. 2.16
Answer:-
The total cost of painting the triangular board is 216 Paisa or Rs. 2.16
Used formulae:-
→ Area of a triangle whose sides are a , b and c units by Heron's formula
√[S(S-a)(S-b)(S-c)] sq.units
Where, S = (a+b+c)/2 units
→ Area of the triangle = (1/2)ab sq.units
→ 1 Rupee = 100 paisa