Question

3) The heat generated is 5.4 x 10^ J when a potential difference of 50 V is applied to a coil. Find the current in the coil when passed for 3 minutes to generate this heat.​

Answer 1

Answer:

Heat produced , H=I

2

Rt

here,

t

H

5

=I

5

2

R

5

=10⇒I

5

=

5

10

=

2

. This is the current through resistor 5Ω.

Voltage across resistor 5Ω is V

5

=I

5

R

5

=

2

×5=5

2

V

As resistors (4,6) and 5 are in parallel, so potential across (4,6) is equal to V

5

.

As resistor 4 and 6 are in series so current through each resistor I

4

=I

6

=

4+6

V

5

=

4+6

5

2

=

2

2

Heat produce in resistor 4 per sec =I

4

2

R

4

=(

2

2

)

2

×(4)=2cal/sec