Question

3. The mass of the earth is 6 x 1024 kg and the mass of the moon is 74 ~1022 kg. The distance between the cards
and the moon is 3.84 x 105 km. Calculate the force exerted by the earth on the moon.
Take, G - 6.7 x 10-11Nm2 kg
(CA.S.E. 2014
Herc
my = 6 x 1024 kg​

Answer 1

Answer:

ANSWER

We know the force of attraction between two object is given by the formulaF=

R

2

GMm

=

(3.84×10

8

)

2

6.7×10

−11

×6×10

24

×7.4×10

22

=2.0×10

20

N

Answer 2

$\huge \sf {\fbox{\fbox{\red{\fbox{Answer:}}}}}$

$\huge \bf{Given:-}$

$\sf {→Mass \: of \: the \: earth,m_1 = 6 \times{{10}^{24} }}$

$\sf {→Mass \: of \: the \: moon,m_2 = 7.4\times{{10}^{22} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{5} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = (3.84\times{{10}^{5} \times 1000)m }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{8}m}}$

$\huge \bf{To \: find:- }$

$\sf{⇒Force \: exerted \: to \: one \: body \: to \: another \: body.}$

$\huge \bf{Formula \: used: - }$

$\leadsto\sf{F =G \times \frac{m_1 \times m_2}{r^2} }$

$\huge \bf{Concept \: used: - }$

$\sf{Gravitational \: constant,G=6.7 \times {10}^{- 11N} N{m}^{2}k {g}^{ - 2} }$

$\huge\bf{According \: to \: Question:-}$

$\bf{F = \frac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22}} {(3.84 \times {10}^{8} )^{2} } = 2.01 \times {10}^{20} newtons}$

$\sf\longmapsto{2.01 \times {10}^{20} newtons}$

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