Question

3. The measure ofone side of a right triangular field is 42 m. If the difference of the lengths of
bypotenuse and the other is 14m, find the sides of the triangle and its area.​

Answer 1

Let the perpedicular, p=4.2 m and base is b m, hypotenuse is h m.

Then by the given question, h-b=14⇒h=b+14

Then by Pythagoros's theorem,

p²+b²=h²

or, (4.2)²+b²=(b+14)²

or, 17.64+b²=b²+2.b.14+196

or, 17.64=28b+196

or, 28b=-178.36

or, b=-178.36/28

or, b=-6.37

Since any side of a triangle can't be negative that means the datas given are wrong.