3. The momentum of a body is increased by 20%.
The percentage increase in kinetic energy is
(a) 54
(b) 44
(c) 100
(d) 50
6.
Answers
Answered by
3
Answer:
44
Explanation:
Let now see what happens when you increase by p by 20%. so if you increase the momentum by 20%(1.2) , the kinetic energy will increase by a factor of 1.44 or, in percentage, by 44%.
Answered by
2
Explanation:
ke=p^2/2m
let new momentum be p+20(p) /100
=6p/5
new kinetic energy be
ke'= p'^2/2m
is (6p/5)^2/2m
= 36p^2/25/2m
=36/25(p^2/2m)
=36/25(ke)
that is ke'=36/25(ke)
by percentage
36/25(ke) /(ke) ×100
=144% more
which means 144%-100%=44%
so answer is 44%
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