Question

3.


The motion of a body is given by the equation
dv/dt = 3 – 2v, where v is velocity in m/s and t
in second. The acceleration of particle when
its velocity is 1 m/s, will be
(1) 1 m/s2
(2) -1 m/s2
(3) 3 m/s2
(4) -2 m/s2​

Answer 1

Answer:

Answer is (4)-2m/sec^2

Answer 2

Answer:

The acceleration of particle will be 1m/s²i.e.option(1).

Explanation:

The equation given in the question is,

$\frac{dv}{dt}=3-2v$       (1)

Where,

$\frac{dv}{dt}$=rate of change of velocity

v=velocity with which the body is moving=1m/s      (given)

And we know that the acceleration is defined at the rate of change in velocity. Which is given as,

$a=\frac{dv}{dt}$       (2)

a=acceleration of the body

By equating equations (1) and (2) we get;

$a=3-2v$       (3)

By substituting the value of v in equation (3) we get;

$a=3-2(1)$

$a=3-2=1m/s^2$

Hence, the acceleration of particle will be 1m/s²i.e.option(1).