Math, asked by arushitiwari2020, 2 months ago

3. The number 7249x4 is divisible by 4, where x is a non-zero digit. Find all possible values of x.​

Answers

Answered by pulakmath007
2

SOLUTION

GIVEN

The number 7249x4 is divisible by 4, where x is a non-zero digit.

TO DETERMINE

All possible values of x

CONCEPT TO BE IMPLEMENTED

Divisibility Rule of 4 :

A number is divisible by 4 if the last two digits of the number are divisible by 4

EVALUATION

Here the given that the number 7249x4 is divisible by 4

Since the number is divisible by 4

So the last two digits of the number are divisible by 4

Thus x4 is divisible by 4

∴ x = 0 , 2 , 4 , 6 , 8

FINAL ANSWER

Hence the required possible values of x are

0 , 2 , 4 , 6 , 8

━━━━━━━━━━━━━━━━

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1. Find the values of A and B if the given number 7A5798B8 is divisible by 33.

https://brainly.in/question/11968792

2. If the sum of three consecutive natural number is 42 which is the largest number

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3. find the sum of following series: the multiple of 4 from 4 to 100 inclusive

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Answered by itzheartcracker13
1

Step-by-step explanation:

SOLUTION

GIVEN

The number 7249x4 is divisible by 4, where x is a non-zero digit.

TO DETERMINE

All possible values of x

CONCEPT TO BE IMPLEMENTED

Divisibility Rule of 4 :

A number is divisible by 4 if the last two digits of the number are divisible by 4

EVALUATION

Here the given that the number 7249x4 is divisible by 4

Since the number is divisible by 4

So the last two digits of the number are divisible by 4

Thus x4 is divisible by 4

∴ x = 0 , 2 , 4 , 6 , 8

FINAL ANSWER

Hence the required possible values of x are

0 , 2 , 4 , 6 , 8

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1.1. Find the values of A and B if the given number 7A5798B8 is divisible by 33.

https://brainly.in/question/11968792

2. If the sum of three consecutive natural number is 42 which is the largest number

https://brainly.in/question/33151821

3. find the sum of following series: the multiple of 4 from 4 to 100 inclusive

https://brainly.in/question/22196432

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