Question

3. The number of atoms present in one mole
an element is equal to Avogadro number
Which of the following element contains the
greatest number of atoms?
(a) 4 g He
(b) 46 g Na
(c) 0.40 g Ca (d)12 g He​

Answer 1

So Here is your answer :-

(d) is the correct answer because

The molar mass of he = 4g

.

Then Given weight /Atomic weight

.

No. of moles = 12/4

= 3 moles.

.

Then,

=3* 6*10^23

= 18*10^23

=1.8*10^24

Answer 2

Answer:

Explanation:(d) is the correct answer because

The molar mass of he = 4g

.

Then Given weight /Atomic weight

.

No. of moles = 12/4

= 3 moles.

.

Then,

=3* 6*10^23

= 18*10^23

=1.8*10^24