Question

(3) The parallel sides of a trapezium shaped field are 72 m and 28 m anddistance between them is 50 m. Find the cost of levelling the field, at the rate of 4rs per m/2​

Answer 1

Step-by-step explanation:

Given; a = 72

b = 28

h = 50

Formulae ; A = 1/2 ( a+b ) h

Area = 1/2 ( 100 ) 50 m^2

Area = 2500m^2

cost of leveling 1m^2 = 4Rs

therefor .... cost of leveling 2500 m^2

= 2500 × 4 Rs

= 10000 Rs