Question

3. The peak value of a sine wave is 400 V. Its average value is
(1/1 Point)
a) 254.6 V
b) 282.6 V
c) 400 V
d) 565.5 V​

Answer 1

Option (a) $\mathsf{254.6}$ V

The peak value of a sine wave is $\mathsf{400}$ V. Its average value is $\mathsf{254.6}$ V.

Explanation:

Let us know Average Voltage Equation first in order to solve the problem:

• $\displaystyle \mathsf{V_{ave}=\frac{2}{\pi}\:V_{p}=0.637\:V_{p}}$

• where $\mathsf{V_{ave}}$ is average voltage and $\mathsf{V_{p}}$ is peak voltage.

Let us use the first relation with the given condition of peak value $\mathsf{V_{p}=400}$ V.

$\therefore \mathsf{V_{ave}=\frac{2}{\pi}\times 400}$

$\Rightarrow \mathsf{V_{ave}=254.6}$ (approximately)

Answer: Option (a) $\mathsf{254.6}$ V

Answer 2

Answer:

2

Explanation: