Question

3. The radius of a hemispherical dome of a
temple is 21 m. Find the cost of painting its
outer surface at the rate of 80 / m2.​

Answer 1

Answer:

221760

Step-by-step explanation:

outer surface area = 2πr^2

cost = 80*2*22/7*21*21

=221760

Answer 2

The answer is Rs 221,558.4

GIVEN

The radius of a hemispherical dome of a

temple is 21 m.

TO FIND

the cost of painting its outer surface at the rate of 80 / m²

SOLUTION

We can simply solve the above problem as follows;

Radius of the hemispherical dome = 21 m

Curved surface are of hemisphere = 2πr²

Putting the value in the above formula we get;

Area = 2 × 3.14 × 21 × 21 = 2769.48 m²

Cost of painting 1 m² of area = Rs 80

Cost of painting 2769.48 m² of area = 80 × 2769.48 = Rs 221,558.4

Hence, The answer is Rs 221,558.4

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