Question

3. The roots of equation 3x2 – 7x- 5 = 0 are
(a) real and equal
(6) imaginary
(c) real, unequal and rational
(d) real, unequal and irrational​

Answer 1

Step-by-step explanation:

(d) real, unequal and irrational

Answer 2

Answer:

The nature of the roots of the quadratic equation $3x^{2} -7x-5=0$ are imaginary

Step-by-step explanation:

• A quadratic equation is a type of equation whose degree is two, a quadratic equation can be represented as

                            $ax^{2} +bx+c=0$

• the corresponding root or the value of x that satisfies the quadratic equation is given by the formula

                 $x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}$     or $x=\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

From the question, we have given a quadratic equation of the form

$3x^{2} -7x-5=0$

as compared with the standard equation we get

$a=3\\b=-7\\c=-5$

substitute these values to get the roots

$x=\frac{7+\sqrt{49-4*5*3} }{6} =\frac{7+3.3i}{6} \\x=\frac{7-\sqrt{49-4*5*3} }{6} =\frac{7-3.3i}{6}$

that is the values of x are imaginary because of the presence of i(iota)