Question

3)
The
solution
of 2) 16y = 40 + 4y​

Answer 1

Answer:

16y-4y=40

12y=40

y =40/12

y=10/3

Answer 2

$\huge\mathbb\red{SOLUTION}$

16y = 40 + 4y

16y - 4y = 40

12y = 40

y = 40/12

y = 3.33333....