Question

(3) The square of a term in the arithmetic
sequence 2, 5, 8, ..., is 2500. What
is its position?​

Answer 1

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The square of the nth term is 2500

So, the nth term will be = √2500

= 50

AP : 2,5,8.....

Let a be the first term, d be the common difference of the given AP

$a _{n} = 50$

$a = 2 \\ d = a _{2} - a _{1} \\ = 5 - 2 = 3$

$a _{n } = a + (n - 1)d \\ 50 = 2 + (n - 1)3 \\ 50 - 2 = (n - 1)3 \\ 48 = (n - 1)3 \\ \frac{48}{3} = (n - 1) \\ 16 = n - 1 \\ n = 16 + 1 \\ n = 17$

The nth term will be the 17th term of the given AP

Answer 2

Answer:

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