Question

3) The sum of first 'n' terms of an AP is given by Sn = 2n^ + 3n. Find
the 16th term of the AP.
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Answer 1

Answer:

Since it's not clear I am assuming that it's 2n²

So, Sn=2n²+3n

Then, a16 = S16-S15

S16= 2×16² + 3×16 = 521+48= 560

S15= 2×15² + 3×15 = 450+45= 495

Hence, a16= 560-495= 65

Answer 2

Answer:

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