Question

3. The sum of first two angles of a triangle is 108° and the sum of the last two angles is
132º. Find the angles.​

Answer 1

${\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}}$

Question

⠀⠀⠀⠀• The sum of first two angles of a triangle is ⠀⠀⠀⠀⠀108° and the sum of the last two angles is

⠀⠀⠀⠀⠀132º Find the angles.

Answer

⠀⠀⠀⠀⠀•∠A= 48°

⠀⠀⠀⠀⠀• ∠B= 60°

⠀⠀⠀⠀⠀• ∠C = 72°

Given

⠀⠀⠀⠀• Sum of first two angles is 108°

⠀⠀⠀⠀• Sum of last two angles is 132°

To Calculate

⠀⠀⠀⠀• Angles __?

Step by step explanation

⠀⠀⠀⠀⠀

Let The angles of triangles be ∠A,∠B,∠C

∠A+∠B+∠C = 180° ( ${\sf{\red{Angle\: Sum \: Property}}}$ )

∠A+∠B= 108° ( ${\sf{\red{Given}}}$ )

Putting,

➫ 108° + ∠C = 180°

➫ ∠C= 180° - 108°

${\boxed{\blue{\tt{➫∠C= 72° }}}}$ ______________(1)

∠B+∠C= 132°

Putting value of C from eq 1

➫∠B+72°=132

➫ ∠B = 132-72

${\boxed{\blue{\tt{➫ ∠B= 60°}}}}$ ______________(2)

∠A+∠B= 108°( ${\sf{\red{Given}}}$ )

Putting value of B from eq 2

➫ ∠A+60°= 108°

➫ ∠A = 108°-60°

${\boxed{\blue{\tt{➫∠ A= 48°}}}}$

${\huge{\underline{\underline{\sf{\blue{Hence :-}}}}}}$

⠀⠀⠀⠀⠀•∠A= 48°

⠀⠀⠀⠀⠀• ∠B= 60°

⠀⠀⠀⠀⠀• ∠C = 72°

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