Question

perfect square number so obtained?
(27) Find the smallest square number that is civisible by each 91
the number 8.15 and 20? please give me the answers ​

Answer 1

Answer:

L.C.M. of 8, 15 and 20 is 120.

Prime factors of 120 = 2 x 2 x 2 x 3 x 5

Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.

\therefore120\times2\times3\times5=3600∴120×2×3×5=3600

Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600.