3 The sum of the 4th and 8th terms of an AP is
24 and the sum of the 6th and 10th terms is
44. Find the first three terms of the AP.
1.
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Answer:
Step-by-step explanation:
a4 + a8 = 24
(a + 3d) + (a + 7d) = 24
a + 3d + a + 7d = 24
2a + 10d = 24 {divided by 2}
a + 5d = 12 ------- eq1
a6 + a10 = 44
(a + 5d) + (a+ 9d) = 44
a + 5d + a + 9d = 44
2a + 14d = 44 {divided by 2}
a + 7d = 22 ------- eq2
From 1 and 2
a + 7d = 22
a + 5d = 12
2d = 10
2d = 10
d = 10/2
d = 5
From 1
a + 5d = 12
a + 5(5) = 12
a + 25 = 12
a = 12 - 25
a = -13
AP : -13, -8, -3
The terms of AP are written in the form - a, a+d, a+2d, a+3d........
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