Math, asked by noel27joel3, 1 month ago

3. The top of a ladder of length 15m reaches a window 9m above the ground

.What is the distance between the base of the wall and that of the ladder?​

Answers

Answered by MrGOAT
2

Step-by-step explanation:

The following condition form a right anled triangle

hypotenuse = 15

height = 9

let the remaining side be x

by pythagoras thm.

15^2 = 9^2 + x^2

225=81+ x^2

225-81= x^2

144= x^2

taking sq. roots

12 = x

Therefore distance between ladder and wall is 12 m

Answered by kartik2507
1

Answer:

12 m

Step-by-step explanation:

the length of the ladder = 15 m

height of window above the ground = 9 m

it forms a right angle triangle

the ladder length will be it's hypotenuse

height of window above ground will be opp side

according to phythagoras theorem

hyp² = adj² + opp²

15² = adj² + 9²

225 = adj² + 81

adj² = 225 - 81

adj² = 144

adj = ✓144

adj = 12 m

distance between base of wall and ladder = 9 m

Hope you get your answer

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