Question

3. The volume of H, gas and N, gas which are formed by the decomposition of 65 g of NH, at STP.
a) 1:4
b) 3:1
c) 2:3
d) 1:2 ​

Answer 1

Answer:

N

2

+3H

2

⟶2NH

3

Number of moles of N

2

in 140g=

28

140g

=5 moles of N

2

Number of moles of H

2

in 30g=

2

30

=15 moles of H

2

moles N

2

+3H

2

⟶2NH

3

at t=0 5 15 -

after reaction 5−5×1 15−3×5 2×5

Thus 10 moles of NH

3

produced after reaction

as number of moles=

volume at STP

volume of product

⇒10=

22.4L

V

⇒V=224L