3. The volume of H, gas and N, gas which are formed by the decomposition of 65 g of NH, at STP.
a) 1:4
b) 3:1
c) 2:3
d) 1:2
Answers
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1
Answer:
N
2
+3H
2
⟶2NH
3
Number of moles of N
2
in 140g=
28
140g
=5 moles of N
2
Number of moles of H
2
in 30g=
2
30
=15 moles of H
2
moles N
2
+3H
2
⟶2NH
3
at t=0 5 15 -
after reaction 5−5×1 15−3×5 2×5
Thus 10 moles of NH
3
produced after reaction
as number of moles=
volume at STP
volume of product
⇒10=
22.4L
V
⇒V=224L
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