Question

3.
Theoritical yield of NH, obtained in Haber's process by reacting 56 g of N, and 12 g of H, is
a) 34 g
b) 68 g
c) 102 g
d) 136 g [
Cu
CUCOoundCHOH as the amountst​

Answer 1

Answer:

Correct option is

A

3.33

N

2

+3H

2

→2NH3

Here.

28 g N

2

reacts with 6 g of H

2

So,

50 g of N

2

react with

28

6

×50g−H

2

=10.7g but we have only 10g so H

2

is limiting reagent..

6 g H

2

gives 34g NH

3

10g H

2

will give

6

34

×10=56.67g−NH

3

So number of moles of NH

3

formed is,

=

Molar−mass

Given−mass

=

17

56.67

=3.33−moles

Explanation:

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