Question

3
Use the method of simultaneous
operations on RHS and LHS to solve the
given equations.
(i) 8-3x = 11

(v) _ = 2
15
Answer both please ​

Answer 1

Answer:

x=-1

$8 - 3x = 11 \\ 8 = 11 + 3x \\ 8 - 11 = 3x \\ 3x = - 3 \\ x = - 3 \div 3 \\ x = - 1$