odinary chlorine gas has 2 chlorine 35 and chlorine 37 in the ratio of 3:1.Calculate the relative atomic mass of chlorine
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Chlorine has two isotopes namely ³⁵Cl and ³⁷Cl
³⁵Cl:³⁷Cl=3:1
Let the relative abundance of ³⁵Cl be 3x % and ³⁷Cl be x %
3x+x=100⇒4x=100⇒x=25
Relative abundance of ³⁵Cl=3×25=75%
Relative abundance of ³⁷Cl=25%
Atomic mass of chlorine=(75/100×35)+(25/100×37)
=105/4+37/4=142/4=35.5 u(Ans.)
Explanation:
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