Question

3.
What is the magnitude of the gravitational force between the
earth and a 1 kg object on its surface? (Mass of the earth is
6x 1024 kg and radius of the earth is 6.4 x 10 m)​

Answer 1

Answer:

According to the universal law of gravitation:-

$g = \frac{GMm}{ {R}^{2} }$

$Value \: \: of \: \: g=6.67× {10}^{ - 11} Nm/kg$

Applying the formula:-

$= \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 1}{ ({6.4 \times {10}^{6} })^{2} }$

$= \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 1}{ {6.4 \times 6.4\times 10}^{12} }$

$= \frac{6.67 \times 6 \times 10}{6.4 \times 6.4}$

=9.7705078125N

=9.8N (approx)

Newton's Universal law of gravitation states that the force of attraction between two bodies is directly proportional to:

• the square(in better way product) of the masses ;and inversely proportional to:
• the square of the distance between them.