3. What is the sum of all interior angles of a polygon with the following number of sides?
(I) 3
(ii)5
(iii) n
(iv) 9
(v)12
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Answer:
Sum of interior angles of any polygon is = (n - 2) X 180
I) ( n - 2) x 180
when n = 3
( 3 - 2) x 180
= 1 X 180
= 180.
ii) ( n - 2) x 180
when n = 5
( 5 - 2) x 180
= 3 X 180
= 540.
iv) ( n - 2) x 180
where n = 9
( 9 - 2) X 180
= 7 x 180
= 1260.
v) ( n - 2) x 180
where n = 12
( 12 - 2) x 180
= 10 x 180
= 1800.
Step-by-step explanation:
I hope this helps you
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