3. Which is the correct relationship:
(a) E1 (H)=1/2 E2 of (He+)=1/3 E3 (Li2+)=1/4 E4(Be3+)
(b) E1(H) = E2(He+) = E3(Li2+) = E4(Be3+)
(c) E1 (H) = 2E2(He+) = 3E3 (Li2+) = 4E4(Be3+)
(d) None of these
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Given: (a) E1 (H)=1/2 E2 of (He+)=1/3 E3 (Li2+)=1/4 E4(Be3+)
(b) E1(H) = E2(He+) = E3(Li2+) = E4(Be3+)
(c) E1 (H) = 2E2(He+) = 3E3 (Li2+) = 4E4(Be3+)
(d) None of these
To find: Which is the correct one?
Solution:
- Now we have given four options, those are:
- Now we know that E(n) = -13.6 Z^2 / n^2 eV/atom
- For H atom, E1 will be:
-13.6 x 1^2 / 1^2 = -13.6 eV/atom
- For He+ atom, E2 will be:
-13.6 x 2^2 / 2^2 = -13.6 eV/atom
- For Li2+ atom, E3 will be:
-13.6 x 3^2 / 3^2 = -13.6 eV/atom
- For Be3+ atom, E4 will be:
-13.6 x 4^2 / 4^2 = -13.6 eV/atom
- So all are same.
- So the correct option is second.
E1(H) = E2(He+) = E3(Li2+) = E4(Be3+)
Answer:
So the correct option is B. E1(H) = E2(He+) = E3(Li2+) = E4(Be3+)
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