Math, asked by aastha250985, 9 months ago


3. Write the quotient when the sum of a 2-digit number 54 and the number obtained on reversing the digits
divided by
(b) sum of the digits

Answers

Answered by krishanasharmaagra19
1

Answer:

Part i). The Quotient is 12

Part ii). The Quotient is 11

Step-by-step explanation:

Given 2-digit number is 39

number we get by revering the digits = 93

Sum of the numbers = 39 + 93 = 132

Sum of the digits of 39 or 93 = 9 + 3 = 12

Part i).

To find Quotient when 132 divided by 11.

\frac{132}{11}=12

11

132

=12

Part ii).

To find Quotient when 132 divided by 12.

\frac{132}{12}=11

12

132

=11

Therefore, Part i). The Quotient is 12 and Part ii). The Quotient is 11

Answered by amitnrw
1

Given :  the sum of a two digit number 54 and the number obtained by reversing the digit divided by sum of  digit  

To Find : Quotient

Solution:

a two digit number 54

Sum of digit = 5 + 4 = 9

Number reversed = 45

54 + 45 = 99

99 Divided by 9

Quotient = 11

Generalized

Two digit number XY  

Value = 10X + Y

reverse YX

Value = 10Y + X

Sum = 10X + Y + 10Y + X

= 11X + 11Y

= 11(X + Y)

Sum of Digits = X + Y

Hence Quotient  = 11

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