3/x-1+1/x+1=4/x where x not equal to 0,1,-1
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Answered by
32
3/x-1 +1/x+1 =4/x
[3(x+1)+1(x-1)]/(x-1)(x+1)=4/x
[3x+3+x-1]/ x square -1 square=4/x
[4x+2]x=4[x square -1]
4x square+2x=4x square-4
2x= -4
x= -4/2
x= -2
[3(x+1)+1(x-1)]/(x-1)(x+1)=4/x
[3x+3+x-1]/ x square -1 square=4/x
[4x+2]x=4[x square -1]
4x square+2x=4x square-4
2x= -4
x= -4/2
x= -2
siddhartharao77:
Good explanation
Answered by
11
soln=3/x_1 =3_x/x
1/x+1=1+x/x
(3_x)/x+(1+x)/x=4/x
(3_x+1+x)/x=4/x=4/x
4x=4x
4/4=x/x
1=x/x
hence,x=2
1/x+1=1+x/x
(3_x)/x+(1+x)/x=4/x
(3_x+1+x)/x=4/x=4/x
4x=4x
4/4=x/x
1=x/x
hence,x=2
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