3(x-1)^2+(x-1)
factorise completely:
is the answer
(x-1)[3(x-1)]?
Answers
Answered by
4
Answer:
Step-by-step explanation:
No the answer should be (3x-2)(x-1)
friedrice:
how?
3(x-1)^2+x-1
3(x^2+1-2x)+(x-1) 3x^2+3-6x+x-1 3x^2-5x+2 3x^2-3x-2x+2
3x(x-1)-2(x-1) thus (x-1)(3x-2)
Answered by
0
NO
take (x-1) common
then
(x-1) (3x-2)
oh! tysm
why?
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