Question

3(x+1) + 6(x+2) = 6(x-4) - 3(x-1) solve the equation​

Answer 1

Question must be like solve the equation for x (finding variable x)

$\sf \: 3(x + 1) + 6(x + 2) = 6(x - 4) - 3(x - 1)$

➔ 3x + 3 + 6x + 12 = 6x- 24 - 3x + 3

➔ 9x + 15 = 3x - 21

➔ 9x - 3x = -21 - 15

➔ 6x = -36

finally, x = - 6

Answer 2

Given:

• 3(x+1) + 6(x+2) = 6(x-4) - 3(x-1)

Solution:

➛3x + 3 + 6(x + 2) = 6(x - 4) - 3(x - 1)

➛3x + 3 + 6x + 12 = 6x - 24 - 3x + 1

➛3x + 6x - 6x + 3x = - 3 - 12 - 24 + 3

➛9x - 6x + 3x = -15 - 24 + 3

➛3x + 3x = - 39 - 3

➛6x = - 36

➛x = - 36/6

➛x = - 6

More to know:

• An equation is a condition on a variable such that two expressions in the variable have equal value.
• The value of the variable for which the equation is satisfied is said to be the solution of the equation.
• An equation remains the same if the LHS and the RHS are interchanged. The variable for which the value is to be found is isolated and the solution is obtained.
• Solving an equation depends on what type of equation that we are dealing with. The equations can be Linear equations, Quadratic equations, rational equations, or Radical equations.

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