(3 - x )² + 3 ² = 6² + x².
Find the value of x.
Give brief answers
Nikki57:
what's the answer
Answers
Answered by
3
(3-x)²+3²= 6²+x²
9+x²-2x+9=36+x²
9+9+x²-2x=36+x²
18-2x=36
-2x=36-18
-2x=18
x=-9
hope u like it ..
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9+x²-2x+9=36+x²
9+9+x²-2x=36+x²
18-2x=36
-2x=36-18
-2x=18
x=-9
hope u like it ..
plz Mark as brainliest
Answered by
0
Hi friend,
(3-x)^2+3^2=6^2+x^2
[Identity-2 (a-b)^2=a^2-2ab+b^2
(3)^2-2*3*x+(x)^2+3^2=6^2+x^2
9-2*3*x+x^2=36+x^2
9-6x+x^2+9=36+x^2
9+9-6x+x^2=36+x^2
18-6x+x^2=36+x^2
-6x+x^2=36-18+x^2
-6x+x^2=18+x^2
-6x=18+x^2-x^2
-6x=18
x=18/-6
x=-2
Hope it helped you..................and if not helpful report it I don't have any problem.............
(3-x)^2+3^2=6^2+x^2
[Identity-2 (a-b)^2=a^2-2ab+b^2
(3)^2-2*3*x+(x)^2+3^2=6^2+x^2
9-2*3*x+x^2=36+x^2
9-6x+x^2+9=36+x^2
9+9-6x+x^2=36+x^2
18-6x+x^2=36+x^2
-6x+x^2=36-18+x^2
-6x+x^2=18+x^2
-6x=18+x^2-x^2
-6x=18
x=18/-6
x=-2
Hope it helped you..................and if not helpful report it I don't have any problem.............
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