Question

3 (x-3 )=5(2x+1) solve by transposing

Answer 1

Given:

A linear equation 3 (x - 3) = 5( 2x + 1).

To find:

The solution by transposing method.

Solution:

As we know that in a transposing method, all the same variables are taken to the left-hand side (LHS) while constants are taken to the right-hand side (RHS). While taking the terms from one side to the other, the sign changes.

Now,

we have,

$3 (x - 3) = 5( 2x + 1)$

After opening brackets, we have,

$3x - 9 = 10x + 5$

Now, after moving the variable '10x' to LHS and constant '-9' to RHS, we have,

$3x - 10x = 9 + 5$

$- 7x = 14$

Now, on multiplying the (-1) on both sides, we have,

$7x = - 14$

After dividing both sides by 7, we get

$x = - 2$

Hence, using the transposing method, the value of x is -2.

Answer 2

3(x-3) =5(2x-1)

3x-9=10x-5

-9+5=10x-3x

-4=7x

x=4/7