Math, asked by nawneet73, 1 year ago

3^x+3^-x=2
by factorisation method

Answers

Answered by shashank5328
0

Answer:

(3^-x =1/3^x)

Step-by-step explanation:

3^x +1/3^x +2=0

(9x^2 +1+6x) =0

9 x^2 +6x+1=0

(3x+1)(3x+1)=0

x =--1/3

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