3^x+3^-x=2
by factorisation method
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Answer:
(3^-x =1/3^x)
Step-by-step explanation:
3^x +1/3^x +2=0
(9x^2 +1+6x) =0
9 x^2 +6x+1=0
(3x+1)(3x+1)=0
x =--1/3
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