3^x+3^-x=2 solve the equation.
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3ˣ+3⁻ˣ=2
3ˣ+1/3ˣ=2
Let 3ˣ=y
y+1/y=2
y²+1=2y
y²-2y+1=0
(y-1)²=0
y=1
3ˣ=1
x=0
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