Question

3(x_4) wholesquare _5(x_4)=12

Answer 1

3(x^2+4-4x)-5x+20=12

3x^2+12-12x-5x=32

3x^2-17x=24

3x^2-9x-8x-24=0

3x(x-3)-8(x-3)=0

x-3=0

x=3

3x-8=0

3x=8

x=8/3

Answer 2

Answer:

Step-by-step explanation:

i just simplified it hope it helps.....

[3(x-4)]^2-5(x-4)=12

[3x-12]^2-5x+20-12=0

9x^2-72x+144-5x+20-12=0

9x^2-77x+152=0..