3^x=9 3^y, 8 2^y-4^x,solve for x and y
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3,ki power x = 9
3power x = 3²
x=2 because base same hoti h to power equal ho jati h
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The value of x = 1
The value of y = -1
Step-by-step explanation:
Given :-
3^x=9 3^y, 8 2^y=4^x
To find:-
solve for x and y
Solution:-
Given that
3^x = 9 3^y
=>3^x /3^y=3²
since a^m/a^n=a^(m-n)
=>3^(x-y)=3²
Since bases are equal then exponents must be equal
x-y=2
y=x-2-------(1)
and
8×2^y = 4^x
=>2³×2^y = (2²)^x
since a^m×a^n= a^(m+n)
=>2^(3+y)=2^2x
Since bases are equal then exponents must be equal
3+y=2x
=>3+x-2=2x
=>1+x=2x
=>2x-x=1
x=1
from (1)
y=1-2
y=-1
Answer:-
The value of x = 1
The value of y = -1
Check:-
1)If x=1 and y=-1 then
3¹=9(3-¹)
=>3=9/3
=>3=3verified
2) 8(2-¹)=4¹
since a^-n=1/a^n
8/2=4
4=4
verified
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