Question

3 x raised to 4 minus 4 x raised to 3 plus 0 x raised to2 minus 3 x minus 1

Answer 1

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${3x}^{4} - {4x}^{3} + 0 {x}^{2} - 3x - 1$

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${3x}^{4} - 4 {x}^{3} - 3x - 1$

$3 {x}^{4} - 3x - 1 - 4 {x}^{3}$

$3x( {x}^{3} - 1) - 1(1 + {4x}^{3} )$

$3x( {x}^{3} - {1}^{3} ) -1(1 + {4x}^{3} )$

$3x((x - 1)( {x}^{2} + 1 + x) - 1(1 + {4x}^{3} )$

$3x(x - 1)( {x}^{2} + x + 1) - 1(1 + {4x}^{3} )$

Here is your answer^^^^

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