Question

3. ਹੇਠ ਦਿੱਤੇ ਰੇਖੀ ਸਮੀਕਰਣ ਜੋੜੇ ਦਾ ਹੱਲ ਪਤਾ ਕਰੋ
X+ y = 16, x - y = 4 Find the Solution of
the following pair of linear equations.
X+ y = 16, x - y = 4 Afra Prach
समीकरण युग्म का हल ज्ञात कीजिए x+ y = 16,
x - y = 4*
O x=6 ,y =10
O x= 4, y=12
O x = 10, y = 6
x = 10, y= 5​

Answer 1

Answer :-

• x = 10
• y = 6

Given :-

• x + y = 16
• x - y = 4

To Find :-

• Values of x and y.

Solution :-

Here

• x + y = 16
• x - y = 4

→ x + y = 16 ...i)

→ x - y = 4 ...ii)

Add eq i) and ii)

⇒ x + x + y - y = 16 + 4

⇒ 2x + 0 = 16 + 4

⇒ 2x = 20

⇒ x = 20/2

⇒ x = 10

Put the value of x in eq i)

⇒x + y = 16

⇒10 + y = 16

⇒y = 16 - 10

⇒y = 6

Hence, the value of x and y are 10 and 6 respectively.

Answer 2

Question:-

Find the Solution of the following pair of linear equations.

X+ y = 16, x - y = 4

a) x=6 ,y =10

b) x= 4, y=12

c) x = 10, y = 6

d) x = 10, y= 5

Answer:-

• The value of x is 10.
• The value of y is 6.

Solution:-

• x + y = 16........eq (1)
• x - y = 4...........eq (2)

$\large { : \implies \: x = 16 - y}$

Substitute value of x in eq 2.

$\large { : \implies \: (16 - y) - y = 4}$

$\large { : \implies \: 16 - 2y = 4}$

$\large { : \implies \: - 2y = 4 - 16}$

$\large { : \implies \: - 2y = - 12}$

$\large { : \implies \: y = \frac{ - 12}{ - 2} }$

$\large { : \implies \: y = 6}$

Put value of y in eq 1

$\large { : \implies \: x + 6 = 16}$

$\large { : \implies \: x = 16 - 6}$

$\large { : \implies \: x = 10}$

Hence,

• The value of x is 10.
• The value of y is 6.

The correct option is (a)