Math, asked by sparsh8687, 3 days ago

(3)/(x+y)+(2)/(x-y)=3 (2)/(x+y)+(3)/(x-y)=(11)/(3)​

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Answered by nsdivyausundhar
2

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kajal10105

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let 1/x+y be p

1/x-y be q

so the eqn is

3p+2q=3

2p+3q=11/3

Eliminate the equation

2[3p+2q=3] ------------1

3[2p+3q=11/3]----------2

subtract the equation

6p+4q=6

6p+9q=11

_ _ _

___________

-5q=-5

q=-5/-5

q=1

put the value of q in eqn 1

6p+4q=6

6p+4(1)=6

6p+4=6

6p=6-4

6p=2

p=2/6

p=1/3

1/x+y=p=1/3

1/x+y=1/3

3=x+y--------------3rd eqn

1/x-y=q=1

1/x-y=1

x-y=1---------4th eqn

x=1+y

put the value of x in eqn 3rd

3=x+y

3=1+y+y

3=1+2y

3-1=2y

2=2y

2/2=y

y=1

put the value of y in eqn 4th

x=1+y

x=1+1

x=2

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