Question

(√3)^x+y=7 and (√2)^x+y=32 then find 2x+y

Answer 1

Step-by-step explanation:

$( \sqrt{3} )^{x} + y = 7 \\ \\ {( \sqrt{2}) }^{x} + y = 32 \\ \\ {( \sqrt{2}) }^{x} - {( \sqrt{3} )}^{x} = 25 \\ \\ x = \frac{2 log_{10}(25) }{ log(2) - log(3) } \\ \\ x = - 15.87$

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