3(y-2)=2(y-1)-3
please tell me
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The answer is y = 1
Explanation:
3(y-2) = 2(y-1)-3
3y−6=2(y−1)−3
3y−6=2y−2−3
3y−6=2y−5
3y−6−2y=−5
y−6=−5
y=−5+6
y = 1
Explanation:
3(y-2) = 2(y-1)-3
3y−6=2(y−1)−3
3y−6=2y−2−3
3y−6=2y−5
3y−6−2y=−5
y−6=−5
y=−5+6
y = 1
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