Math, asked by Moazzam3032, 10 months ago

×/3+y/4=11,5×/6-y/3=7






Answers

Answered by mansipatel5
0
X/3+y/4=11
multiplying by 12, then
4x+3y =132.......(1)
5x/6-y/3+7 =0
5x/6-y/3= -7
multiplying by 18, then
15x-6y= -126........(2)
in equation (1) multiplying by 2, then, 8x+6y =264........(3)
(2)+(3)
we get, 23x =138
ie, x= 138/23= 6
ie, x=6
put the value of x into equation (1), we get,
24+3y=132
3y =108
y =36
we get the values are x=6 and
y = 36
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