Question

3 years ago, a father's age was twice the sum of ages of his 4 sons. In 3 years time, the father's will age will be equal to sum of ages of the sons. Find the present age of father​

Answer 1

Answer:

question is incorrect or incomplete . Please check the question first then write the correct question

Step-by-step explanation:

Answer 2

Answer:

The present age of the father = 39

Step-by-step explanation:

Given,

3 years ago, father's age was twice the sum of the ages of his 4 sons

In 3 years' time, the father's will age will be equal to the sum of the ages of the sons

To find,

The present age of the father

Solution:

Let 'x' be the present age of the father and 'y' be the sum of the present ages of four sons

3 years ago

Age of the father = x-3

Sum of ages of four sons = y -3×4 = y - 12

Since it is given that 3 years ago, the father's age was twice the sum of ages of his 4 sons, we have

x-3 = 2(y-12)

x -3 = 2y -24

x = 2y -24 +3

x = 2y - 21-------------------(1)

After 3 years

Age of father = x+3

Sum of ages of four sons = y + 3×4 = y+12

Since the father's will age will be equal to the sum of the ages of the sons after 3 years, we have

x+3 = y+12

x = y+12-3

x = y+9 ---------------------(2)

Substituting the value of x in equation (1) we get,

y+9 = 2y -21

y = 21+9

y = 30

x = y+9

= 30 +9

x= 39

The value of x = 39

The present age of the father = 39

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