Question

3 years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby is:

Answer 1

$\huge\red{Answer}$

Let age of the baby is x.

3 years ago total age of the family = 5 *17 = 85 years.

Total age of the 5 member at present time,

= 85 + 3*5 = 100 years

Total age of the family at present time including baby,

= 100 + X.

The average of the family including baby at present time,

= 17 years.

(100 +X)/6 = 17

100 +X = 102

X = 102 - 100 = 2 years.

HOPE IT HELPS YOU ☺ !!

Answer 2

Answer:

2years

Step-by-step explanation:

We're told that 3 YEARS AGO, the average age of a family of 5 members was 17 years.

This means that the SUM of their ages was (5)(17) = 85 years.

A baby was born (meaning that there are now 6 family members). We're told that the PRESENT average age of the family members is the SAME.

This means that the sum of the ages is (6)(17) = 102 years.

We're asked for the PRESENT age of the baby.

Since each of the original 5 family members has aged 3 years since the initial average was calculated, the sum of their PRESENT ages is...

85 + (5)(3) = 100.

Since the current sum of the 6 family members is 102, the baby is 102-100 = 2 years old.