Math, asked by ashokepawar, 1 year ago

3 years ago the population of a town was 50000 if the annual increase during 3 suggestive years be @ 5% of 4% and 3% respectively what it is present population

Answers

Answered by math109
1
3 year ago population was 5000
2nd year population=50000×105/100
previous year=500×105×104/100
current population=
5×105×104×103/100=5623800/100
= 56238
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